\(123+132+231+312+213+321=\left(123+321\right)+\left(132+231\right)+\left(312+213\right)=444+363+525=1332\)

Tính bằng cách thuận tiện nhất nhé

123+132+213+231+312+321

=400+400+400

=1200

**** nha

123+132+213+231+312+321

= 400 + 400 + 400

= 400 x 3 

=1200 

Chúc bạn học tốt ! 

Nhớ k cho mình nha

\(123+132+213+312+321\)

\(=\left(123+312\right)+\left(213+132\right)+321\)

\(=435+345+321\)

\(=\left(435+345\right)+321\)

\(=780+321=1101\)

123+132+213+231+312+321

=(123+321)+(213+132)+321

=435+345+321

=(435+345)+321

=780+321

=1101

123 + 132 + 213 + 231 + 312 + 321

= 123 + 132 + 213 + 312 + 231 + 321

= 255 + 525 + 552

= 780 + 552

= 1232

1^2+3^4+5^6+7^8+9^10=3492564909

1.200.400.0=0

sửa giùm mình đề câu a

a, 123+132+231+312+213+312

123+132+213+312+213+312

=(123+213)+(312+312)+(123+132)

= 123×2 + 312 ×2 + 255

= 426 + 624 +255

= 1050 + 255

= 1305

2) 159+195+519+591+915+951

=(159+951)+(519+591)+(195+915)

= 1110+1110+1110

= 1110×3

=3330

a) =1305 

 b)=3330 nha! cánh làm giống conan

1332 nha .

=(132+312)+(123+321)+(213+231) = 444 + 444 + 444 = 1332

=(123+321)+(213+231)+(312+132)

=444+444+444

=888+444

=1332

Vậy kết quả là : 1332

a) 132 + 76 + 868 + 524 + 500

= (132 + 868) + (76 + 524) + 500

= 1000 + 600 + 500

= 2100

b) 200 - 201 + 202 - 203 + 204 - 205 + 206 - 207 + 208 - 209 + 210

= (200 + 210) + (-201 - 209) + (202 + 208) + (-203 - 207) + (204 + 206) - 205

= 410 - 410 + 410 - 410 + 410 - 205

=  0 + 0 + 205

= 205

trả lời nhamh vậy

gooddddddddddddddddddddddddddddddddddd

a/ A= 119+(-213)+212+(-118)+2009

A= ! - 1 + 2009

A= 2009

b/ B=223+132+187-23-32-87

B = 200 + 100 + 100

B = 400

c/ C= -2012+(-596)+(-201)+496+301

C = -2012 - 100 + 100

C = -2012

 d/ D= -329+(15-101)-(25-440)

D = 0

hok tốt!!!

\(a,A=119+\left(-213\right)+212+\left(-118\right)+2009\)

\(A=\left(119+212+2009\right)+\left[\left(-213\right)+\left(-118\right)\right]\)

\(A=2340+\left(-331\right)\)

\(A=2009\)

\(b,B=223+132+187-23-32-87\)

\(B=\left(223+132+187\right)+\left(-23-32-87\right)\)

\(B=542-142\)

\(B=400\)

Theo đề \(\Rightarrow\left(\frac{301-x}{103}+1\right)+\left(\frac{302-x}{102}+1\right)=\left(\frac{303-x}{101}+1\right)+\left(\frac{304-x}{100}+1\right)\)

\(\Leftrightarrow\left(\frac{301-x}{103}+1\right)+\left(\frac{302-x}{102}+1\right)-\left(\frac{303-x}{101}+1\right)-\left(\frac{304-x}{100}+1\right)=0\)

Sau khi đã quy đồng các phân số với các số 1, ta có :

\(\frac{301-x+103}{103}+\frac{302-x+102}{102}-\frac{303-x+101}{101}-\frac{304-x+100}{100}=0\)

\(\Rightarrow\frac{404-x}{103}+\frac{404-x}{102}-\frac{404-x}{101}-\frac{404-x}{100}=0\)

\(\Leftrightarrow\left(404-x\right)\times\frac{1}{103}+\left(404-x\right)\times\frac{1}{102}-\left(404-x\right)\times\frac{1}{101}-\left(404-x\right)\times\frac{1}{100}=0\)

\(\Leftrightarrow\left(404-x\right)\times\left(\frac{1}{103}+\frac{1}{102}-\frac{1}{101}-\frac{1}{100}\right)=0\)

Vì \(\frac{1}{103}< \frac{1}{102}< \frac{1}{101}< \frac{1}{100}\Rightarrow\frac{1}{103}+\frac{1}{102}-\frac{1}{101}-\frac{1}{100}\ne0\)

Để \(\left(404-x\right)\times\left(\frac{1}{103}+\frac{1}{102}-\frac{1}{101}-\frac{1}{100}\right)=0\)thì \(404-x=0\)

\(404-x=0\)

\(\Rightarrow x=404\)

Vậy x=404

Phương trình \(\Leftrightarrow\left(\frac{301-x}{103}+1\right)+\left(\frac{302-x}{102}+1\right)=\left(\frac{303-x}{101}+1\right)+\left(\frac{304-x}{100}+1\right)\)

\(\Leftrightarrow\frac{404-x}{103}+\frac{404-x}{102}=\frac{404-x}{101}+\frac{404-x}{100}\)

\(\Leftrightarrow\left(404-x\right)\left(\frac{1}{103}+\frac{1}{102}-\frac{1}{101}-\frac{1}{100}\right)=0\)

\(\Leftrightarrow404-x=0\)vì \(\left(\frac{1}{103}+\frac{1}{102}-\frac{1}{101}-\frac{1}{100}\right)\ne0\)

\(\Leftrightarrow x=404\)

Vậy phương trình có nghiệm x=404